\(\hat{\vec S}=\dfrac\hbar2\vec\sigma\) with \[\sigma_x=\begin{pmatrix}0&1\\1&0\end{pmatrix},\qquad\sigma_y=\begin{pmatrix}0&-i\\i&0\end{pmatrix},\qquad\sigma_z=\begin{pmatrix}1&0\\0&-1\end{pmatrix}.\]
Properties
\(\sigma_x^2=\sigma_y^2=\sigma_z^2=I\); traceless; eigenvalues \(\pm1\); \(\det\sigma_i=-1\).
\(\sigma_x\sigma_y=i\sigma_z\), \(\sigma_y\sigma_z=i\sigma_x\), \(\sigma_z\sigma_x=i\sigma_y\) (reverse order gives \(-i\)): \(\sigma_i\sigma_j=\delta_{ij}I+i\epsilon_{ijk}\sigma_k\).
\([\sigma_i,\sigma_j]=2i\epsilon_{ijk}\sigma_k\); \(\{\sigma_i,\sigma_j\}=2\delta_{ij}I\).
\((\vec a\cdot\vec\sigma)(\vec b\cdot\vec\sigma)=(\vec a\cdot\vec b)I+i(\vec a\times\vec b)\cdot\vec\sigma\).
For a unit vector \(\hat n\): \((\hat n\cdot\vec\sigma)^{2p}=I\), \((\hat n\cdot\vec\sigma)^{2q+1}=\hat n\cdot\vec\sigma\), hence \[\exp\big[ia(\hat n\cdot\vec\sigma)\big]=I\cos a+i(\hat n\cdot\vec\sigma)\sin a.\]
Eigenvectors of \(\sigma_x,\sigma_y,\sigma_z\) are those of \(\hat S_x,\hat S_y,\hat S_z\) above, with eigenvalues \(\pm1\).
Spin rotation matrix
\(U[R(\theta)]=\exp\Big(-\dfrac{i\,\vec\theta\cdot\vec S}{\hbar}\Big)=\exp\Big(-\dfrac{i\theta}{2}\hat m\cdot\vec\sigma\Big)=I\cos\dfrac\theta2-i\sin\dfrac\theta2\,\hat m\cdot\vec\sigma\).
Rotation about \(x\): \(R_x(\theta)=\begin{pmatrix}\cos\frac\theta2&-i\sin\frac\theta2\\-i\sin\frac\theta2&\cos\frac\theta2\end{pmatrix}\).
To turn \(\hat z\) into \(\hat n(\theta,\phi)\), rotate by \(\theta\) about \(\hat m=(-\sin\phi,\cos\phi,0)\): \[U=\begin{pmatrix}\cos\frac\theta2&-\sin\frac\theta2\,e^{-i\phi}\\\sin\frac\theta2\,e^{i\phi}&\cos\frac\theta2\end{pmatrix}.\]
A \(2\pi\) rotation gives \(U=-I\): spinors change sign.
Example 10.3 The operator \(\hat n\cdot\vec\sigma\)
\(\hat A=\hat n\cdot\vec\sigma\). (a) Write its matrix in terms of \(\theta,\phi\). (b) For \(\hat n\) in the \(xz\)-plane find its eigenvalues.
Solution
(a) \(\hat A=\sin\theta\cos\phi\,\sigma_x+\sin\theta\sin\phi\,\sigma_y+\cos\theta\,\sigma_z=\begin{pmatrix}\cos\theta&\sin\theta\,e^{-i\phi}\\\sin\theta\,e^{i\phi}&-\cos\theta\end{pmatrix}\).
(b) \(\phi=0\): \(\begin{vmatrix}\cos\theta-\lambda&\sin\theta\\\sin\theta&-\cos\theta-\lambda\end{vmatrix}=\lambda^2-1=0\Rightarrow\lambda=\pm1\) (for any \(\hat n\)).
Eigenvectors: \(\left|+\right\rangle_{\hat n}=\begin{pmatrix}\cos\frac\theta2\\e^{i\phi}\sin\frac\theta2\end{pmatrix}\), \(\left|-\right\rangle_{\hat n}=\begin{pmatrix}-e^{-i\phi}\sin\frac\theta2\\\cos\frac\theta2\end{pmatrix}\).
Example 10.4 Time-evolution operator in a field
\(H=\mu\vec\sigma\cdot\vec B\), \(\omega=\mu B/\hbar\). Show \(e^{iHt/\hbar}=I\cos\omega t+\dfrac{i\vec\sigma\cdot\vec B}{B}\sin\omega t\).
Solution
\(\dfrac{iHt}{\hbar}=i\,\dfrac{\mu Bt}{\hbar}\,(\hat n\cdot\vec\sigma)=i\omega t\,(\hat n\cdot\vec\sigma)\) with \(\hat n=\vec B/B\).
Use \(e^{ia\hat n\cdot\vec\sigma}=I\cos a+i\hat n\cdot\vec\sigma\sin a\) with \(a=\omega t\).
Example 10.5 Rotation about \(x\)
Spins in the \(\sigma_z=+1\) state are rotated by \(60^\circ\) about \(x\). Find the fractions with \(\sigma_z=+1\) and \(-1\).
Solution
\(R_x(\pi/3)\begin{pmatrix}1\\0\end{pmatrix}=\begin{pmatrix}\cos30^\circ\\-i\sin30^\circ\end{pmatrix}=\begin{pmatrix}\sqrt3/2\\-i/2\end{pmatrix}\).
\(P(+1)=\tfrac34\), \(P(-1)=\tfrac14\).
Example 10.6 Precession in an arbitrary field
An electron (\(g\)-factor \(g\), \(\vec S=\frac\hbar2\vec\sigma\)) is at rest in \(\vec B=(B_x,B_y,B_z)\), all components non-zero. At \(t=0\) it is in \(s_z=+\frac12\). Find the earliest time at which the spin state is orthogonal to the initial state.
Solution
\(H=-\vec\mu\cdot\vec B=\dfrac{ge}{2m}\vec S\cdot\vec B=E_0|B|\,\hat n\cdot\vec\sigma\), \(E_0=\dfrac{ge\hbar}{4m}\); eigenvalues \(\pm E_0|B|\).
Eigenvectors \(\left|\phi_1\right\rangle=\left|+\right\rangle_{\hat n}\), \(\left|\phi_2\right\rangle=\left|-\right\rangle_{\hat n}\); initially \(\left|\uparrow\right\rangle=\cos\frac\theta2\,e^{-i\phi/2}\left|\phi_1\right\rangle-\sin\frac\theta2\,e^{i\phi/2}\left|\phi_2\right\rangle\) (up to phase).
\(\left\langle \psi(0)\middle|\psi(t)\right\rangle =\cos^2\frac\theta2\,e^{-iE_0|B|t/\hbar}+\sin^2\frac\theta2\,e^{iE_0|B|t/\hbar}\).
This vanishes only if \(\cos^2\frac\theta2=\sin^2\frac\theta2\), i.e. \(\theta=\pi/2\) (\(B_z=0\)). With \(B_z\ne0\) the spin precesses on a cone about \(\vec B\) and never becomes orthogonal.
If \(B_z=0\): \(\cos(E_0|B|t/\hbar)=0\Rightarrow t=\dfrac{\pi\hbar}{2E_0|B|}=\dfrac{2\pi m}{ge|B|}\).
Example 10.7 Eigenvalues of \(\hat S_x+\hat S_y\)
Solution
Example 10.8 Measurements on \(\binom{3+4i}{3}\)
For \(\left|\psi\right\rangle=\binom{3+4i}{3}\) find the outcomes and probabilities of (a) \(\hat S^2\), (b) \(\hat S_z\), (c) \(\hat S_x\).
Solution
\(\left\langle \psi\middle|\psi\right\rangle =25+9=34\).
(a) \(\tfrac34\hbar^2\) with probability 1.
(b) \(P(+\tfrac\hbar2)=\dfrac{25}{34}\), \(P(-\tfrac\hbar2)=\dfrac{9}{34}\).
(c) \(\left\langle x_+\middle|\psi\right\rangle =\dfrac{6+4i}{\sqrt2}\), \(\left\langle x_-\middle|\psi\right\rangle =\dfrac{4i}{\sqrt2}\) \(\Rightarrow P(+\tfrac\hbar2)=\dfrac{26}{34}=\dfrac{13}{17}\), \(P(-\tfrac\hbar2)=\dfrac{8}{34}=\dfrac{4}{17}\).
Example 10.9 Change of basis and time evolution
\(\left|\psi\right\rangle=\sqrt{\tfrac23}\left|\uparrow\right\rangle+\sqrt{\tfrac13}\left|\downarrow\right\rangle\). (a) Write \(\left|\psi\right\rangle\) in the \(\hat S_x\) eigenbasis \(\left|\phi_\pm\right\rangle\). (b) Find \(\left\langle \hat S_x\right\rangle\). (c) With \(H=-\mu_0B\hat S_x\) find \(\left|\psi(t)\right\rangle\).
Solution
(a) Insert \(I=\left|\phi_+\right\rangle\left\langle\phi_+\right|+\left|\phi_-\right\rangle\left\langle\phi_-\right|\): \[\left|\psi\right\rangle=\Big(\frac1{\sqrt3}+\frac1{\sqrt6}\Big)\left|\phi_+\right\rangle+\Big(\frac1{\sqrt3}-\frac1{\sqrt6}\Big)\left|\phi_-\right\rangle=\frac{\sqrt2+1}{\sqrt6}\left|\phi_+\right\rangle+\frac{\sqrt2-1}{\sqrt6}\left|\phi_-\right\rangle.\]
(b) \(\left\langle \hat S_x\right\rangle=\dfrac\hbar2\big(P_+-P_-\big)=\dfrac\hbar2\cdot\dfrac{4}{\sqrt{18}}=\dfrac{\sqrt2}{3}\hbar\).
(c) \(E_\pm=\mp\dfrac{\mu_0B\hbar}{2}\): \(\left|\psi(t)\right\rangle=\dfrac{\sqrt2+1}{\sqrt6}e^{i\mu_0Bt/2}\left|\phi_+\right\rangle+\dfrac{\sqrt2-1}{\sqrt6}e^{-i\mu_0Bt/2}\left|\phi_-\right\rangle\).
Example 10.10 General spinor
\(\left|\psi\right\rangle=\cos\alpha\,\chi_{+}+\sin\alpha\,e^{i\beta}\chi_{-}\) (\(\alpha,\beta\) real). Find \(P(S_x=+\frac\hbar2)\).
Solution